0.03x^2-6x-2500=0

Solution for 0.03x^2-6x-2500=0 equation:

0.03x^2-6x-2500=0

a = 0.03; b = -6; c = -2500;
Δ = b2-4ac
Δ = -62-4·0.03·(-2500)
Δ = 336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{336}=\sqrt{16*21}=\sqrt{16}*\sqrt{21}=4\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-4\sqrt{21}}{2*0.03}=\frac{6-4\sqrt{21}}{0.06}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+4\sqrt{21}}{2*0.03}=\frac{6+4\sqrt{21}}{0.06}
$